Question6.12:Since array references decay into pointers,what's the difference between them? [复制链接]

Q: Since array references decay into pointers, if arr is an array, what's the difference between arr and &arr?
A: The type.
In Standard C, &arr yields a pointer, of type pointer-to-array-of-T, to the entire array. (In pre-ANSI C, the & in &arr generally elicited a warning, and was generally ignored.)Under all C compilers, a simple reference (without an explicit &) to an array yields a pointer, of type pointer-to-T, to the array's first
element.
For a simple array
                          int a[10];
a reference to a has type ``pointer to int,'' and &a is ``pointer to array of 10 ints.'' For a two-dimensional array like
                           int array[NROWS][NCOLUMNS];
a reference to array has type ``pointer to array of NCOLUMNS ints,'' while &array has type ``pointer to array of NROWS arrays of NCOLUMNS ints.''
See also questions 6.3, 6.13, and 6.18.

问题：由于数组引用退化为指针，如果arr是一个数组，那么arr和&arr之间的区别是什么？
回答：区别在于类型。
在标准C中，&arr会产生一个T型数组指针指向整个数组（在ANSI C之前，&arr中的&通常会引出警告，并且通常是被忽略的）。在所有的C编译器中，一个数组的简单的引用（没有&）会产生一个T型指针指向数组的第一个元素。
对于一个简单数组
         int a[10];
一个对于a的引用的类型是“int型数组的指针”，&a则是“10个int数组的指针”。对于二维数组，如
         int array[NROWS][NCOLUMNS];
对array的引用的类型是“NCOLUMNS”个int的数组的指针，而array的类型则是“NROWS个NCOLUMN个int的数组的指针”。
参考问题6.3、6.13和6.18。